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(F)=5F(F-5)-5F^2
We move all terms to the left:
(F)-(5F(F-5)-5F^2)=0
We calculate terms in parentheses: -(5F(F-5)-5F^2), so:We add all the numbers together, and all the variables
5F(F-5)-5F^2
determiningTheFunctionDomain -5F^2+5F(F-5)
We multiply parentheses
-5F^2+5F^2-25F
We add all the numbers together, and all the variables
-25F
Back to the equation:
-(-25F)
F-(-25F)=0
We get rid of parentheses
F+25F=0
We add all the numbers together, and all the variables
26F=0
F=0/26
F=0
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